Trying to get to moodle formulas
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@ -1,8 +1,34 @@
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import xml.etree.ElementTree as ET
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import random
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from math import gcd
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import re
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def create_cloze_question(name, questiontext, correct_answers, wrong_answers, feedback, tags):
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def create_html_table_for_fracture_input(rows: list):
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table_rows = []
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# Tabellenzeilen festlegen
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for i, row in enumerate(rows):
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if (i % 2) == 0:
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table_row = "<tr style='border-bottom: 1px solid black;'>"
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else:
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table_row = "<tr>"
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for cell in row:
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table_row += f"<td style='padding: 5px;'>{cell}</td>"
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table_row += "</tr>"
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table_rows.append(table_row)
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# Tabelle zusammenbauen
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table_html = (
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f"<table style='border-collapse: collapse;'>\n"
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+ "\n".join(table_rows)
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+ "</table>"
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)
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return re.sub("\\s+", " ", table_html)
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def create_cloze_question(name, questiontext, question_math, calcstep_math, correct_answers, wrong_answers, feedback, tags):
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question = ET.Element('question', attrib={'type': 'cloze'})
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name_elem = ET.SubElement(question, 'name')
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@ -13,13 +39,11 @@ def create_cloze_question(name, questiontext, correct_answers, wrong_answers, fe
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text_elem = ET.SubElement(questiontext_elem, 'text')
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# Erstelle die Tabelle für die Lücken
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cloze_text = "<table style='border-collapse: collapse;'>"
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cloze_text += "<tr>"
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cloze_text += f"<td style='border-bottom: 1px solid black; padding: 5px;'>Zähler: {{1:SHORTANSWER:={correct_answers[0]}~%0%{wrong_answers[0][0]}#{wrong_answers[0][1]}}}</td>"
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cloze_text += "</tr>"
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cloze_text += "<tr>"
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cloze_text += f"<td style='padding: 5px;'>Nenner: {{1:SHORTANSWER:={correct_answers[1]}~%0%{wrong_answers[1][0]}#{wrong_answers[1][1]}}}</td>"
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cloze_text += "</tr>"
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rows_list = [
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["Zähler:", f"{{1:SHORTANSWER:={correct_answers[0]}~%0%{wrong_answers[0][0]}#{wrong_answers[0][1]}}}"],
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["Nenner:", f"{{1:SHORTANSWER:={correct_answers[1]}~%0%{wrong_answers[1][0]}#{wrong_answers[1][1]}}}"]
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]
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# Prüfe, ob der Bruch gekürzt werden kann
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if gcd(correct_answers[0], correct_answers[1]) > 1:
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@ -27,14 +51,10 @@ def create_cloze_question(name, questiontext, correct_answers, wrong_answers, fe
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reduced_numerator = correct_answers[0] // common_divisor
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reduced_denominator = correct_answers[1] // common_divisor
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cloze_text += "<tr>"
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cloze_text += f"<td style='border-bottom: 1px solid black; padding: 5px;'>Gekürzter Zähler: {{1:SHORTANSWER:={reduced_numerator}~%0%{wrong_answers[2][0]}#{wrong_answers[2][1]}}}</td>"
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cloze_text += "</tr>"
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cloze_text += "<tr>"
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cloze_text += f"<td style='padding: 5px;'>Gekürzter Nenner: {{1:SHORTANSWER:={reduced_denominator}~%0%{wrong_answers[3][0]}#{wrong_answers[3][1]}}}</td>"
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cloze_text += "</tr>"
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rows_list.append(["Gekürzter Zähler:",f"{{1:SHORTANSWER:={reduced_numerator}~%0%{wrong_answers[2][0]}#{wrong_answers[2][1]}}}"])
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rows_list.append(["Gekürzter Nenner:",f"{{1:SHORTANSWER:={reduced_denominator}~%0%{wrong_answers[3][0]}#{wrong_answers[3][1]}}}"])
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cloze_text += "</table>"
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cloze_text = create_html_table_for_fracture_input(rows_list)
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# Füge die Frage hinzu
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text_elem.text = questiontext + " " + cloze_text
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@ -42,11 +62,15 @@ def create_cloze_question(name, questiontext, correct_answers, wrong_answers, fe
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generalfeedback_elem = ET.SubElement(question, 'generalfeedback', attrib={'format': 'html'})
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text_elem = ET.SubElement(generalfeedback_elem, 'text')
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solution = f"<h3>Lösungshinweise:</h3>"
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solution += "<p>"
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# Musterlösung im LaTeX-Format
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if gcd(correct_answers[0], correct_answers[1]) > 1:
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solution = f"Die Musterlösung ist: \\( \\Large \\displaystyle \\frac{{{reduced_numerator}}}{{{reduced_denominator}}} \\)."
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solution += f"\\( {question_math} {calcstep_math} = \\frac{{{correct_answers[0]}}}{{{correct_answers[1]}}} = \\frac{{{reduced_numerator}}}{{{reduced_denominator}}} \\)."
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else:
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solution = f"Die Musterlösung ist: \\( \\Large \\displaystyle \\frac{{{correct_answers[0]}}}{{{correct_answers[1]}}} \\)."
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solution += f"\\( {question_math} {calcstep_math} = \\frac{{{correct_answers[0]}}}{{{correct_answers[1]}}} \\)"
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solution += "</p>"
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text_elem.text = solution
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@ -97,7 +121,7 @@ for i in range(1, (n+1)):
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# Berechne den gemeinsamen Nenner, der kleiner als 30 sein muss
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common_denominator = lcm(denominator1, lcm(denominator2, denominator3))
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while common_denominator >= 30:
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while common_denominator >= 50:
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denominator1 = random.randint(2, 10)
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denominator2 = random.randint(2, 10)
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denominator3 = random.randint(2, 10)
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@ -121,10 +145,14 @@ for i in range(1, (n+1)):
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# Prüfe, ob der Bruch gekürzt werden kann
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needs_reduction = gcd(result_numerator, common_denominator) > 1
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question_puremath = f"\\Large \\displaystyle \\frac{{{numerator1}}}{{{denominator1}}} {operations[0]} \\left(\\frac{{{numerator2}}}{{{denominator2}}} {operations[2]} \\frac{{{numerator3}}}{{{denominator3}}}\\right) ="
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# Frage im LaTeX-Format
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questiontext = (f"<p>Berechne und kürze das Ergebnis, wenn möglich:</p> "
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f"<p> \\( \\Large \\displaystyle \\frac{{{numerator1}}}{{{denominator1}}} {operations[0]} "
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f"\\left(\\frac{{{numerator2}}}{{{denominator2}}} {operations[2]} \\frac{{{numerator3}}}{{{denominator3}}}\\right) = \\) </p>")
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f"<p> \\( {question_puremath} \\) </p>")
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# Feedback-Ausgabe für notwendigen Zwischenschritt
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calculation_step_math = f"\\frac{{{equivalent_numerator1}}}{{{common_denominator}}} {operations[0]} \\left(\\frac{{{equivalent_numerator2}}}{{{common_denominator}}} {operations[2]} \\frac{{{equivalent_numerator3}}}{{{common_denominator}}}\\right)"
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# Antworten
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correct_answers = [result_numerator, common_denominator]
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@ -153,6 +181,8 @@ for i in range(1, (n+1)):
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questions.append(create_cloze_question(
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f"Addition/Subtraktion von 3 ungleichnamigen Brüchen {i}",
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questiontext,
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question_puremath,
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calculation_step_math,
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correct_answers,
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wrong_answers,
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feedback,
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187
aufgabengenerator_formuals_2brueche_addieren_ungleichnamig_v1.py
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187
aufgabengenerator_formuals_2brueche_addieren_ungleichnamig_v1.py
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@ -0,0 +1,187 @@
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import random
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from math import gcd
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import xml.etree.ElementTree as ET
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def lcm(a, b):
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"""Berechnet das kleinste gemeinsame Vielfache."""
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return abs(a * b) // gcd(a, b)
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def create_formula_question(numerator1, denominator1, numerator2, denominator2, n):
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"""Erzeugt eine Frage im Format 'Formulas'."""
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# GCD und das kleinste gemeinsame Vielfache für die Denominator
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common_denominator = lcm(denominator1, denominator2)
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new_numerator = (numerator1 * (common_denominator // denominator1)) + (numerator2 * (common_denominator // denominator2))
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question = ET.Element('question', attrib={'type': 'formulas'})
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name_elem = ET.SubElement(question, 'name')
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text_elem = ET.SubElement(name_elem, 'text')
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text_elem.text = 'Addition von 2 ungleichnamigen Brüchen {}'.format(n)
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questiontext_elem = ET.SubElement(question, 'questiontext', attrib={'format': 'html'})
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text_elem = ET.SubElement(questiontext_elem, 'text')
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text_elem.text = '''<![CDATA[ <p>Addiere die Brüche und kürze das Ergebnis so weit wie möglich.</p>
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<p>{#A} </p> ]]> '''
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# Allgemeines Feedback
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generalfeedback_elem = ET.SubElement(question, 'generalfeedback', attrib={'format': 'html'})
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text_elem = ET.SubElement(generalfeedback_elem, 'text')
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text_elem.text = ' '
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# Grundlegende Bewertungsinformationen
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ET.SubElement(question, 'defaultgrade').text = '1.0000000'
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ET.SubElement(question, 'penalty').text = '0.3333333'
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ET.SubElement(question, 'hidden').text = '0'
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ET.SubElement(question, 'idnumber').text = ' '
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# Feedback für korrekte und inkorrekte Antworten
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correctfeedback_elem = ET.SubElement(question, 'correctfeedback', attrib={'format': 'html'})
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text_elem = ET.SubElement(correctfeedback_elem, 'text')
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text_elem.text = '''<![CDATA[ <p>Die Antwort ist richtig.</p> ]]> '''
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partiallycorrectfeedback_elem = ET.SubElement(question, 'partiallycorrectfeedback', attrib={'format': 'html'})
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text_elem = ET.SubElement(partiallycorrectfeedback_elem, 'text')
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text_elem.text = '''<![CDATA[ <p>Die Antwort ist teilweise richtig.</p> ]]> '''
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incorrectfeedback_elem = ET.SubElement(question, 'incorrectfeedback', attrib={'format': 'html'})
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text_elem = ET.SubElement(incorrectfeedback_elem, 'text')
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text_elem.text = '''<![CDATA[ <p>Die Antwort ist falsch.</p> ]]>'''
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ET.SubElement(question, 'shownumcorrect')
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varsrandom_elem = ET.SubElement(question, 'varsrandom')
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text_elem = ET.SubElement(varsrandom_elem, 'text')
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text_elem.text = f' '
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# Globale Variablen definieren
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varsglobal_elem = ET.SubElement(question, 'varsglobal')
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text_elem = ET.SubElement(varsglobal_elem, 'text')
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text_elem.text = f'n = [{numerator1}, {numerator2}];\n d = [{denominator1}, {denominator2}];'
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answernumbering_elem = ET.SubElement(question, 'answernumbering')
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text_elem = ET.SubElement(answernumbering_elem, 'text')
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text_elem.text = 'ABCD'
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# Antworten definieren
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answers_elem = ET.SubElement(question, 'answers')
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# Indizes für die Antworten
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partindex_elem = ET.SubElement(answers_elem, 'partindex')
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ET.SubElement(partindex_elem, 'text').text = '0'
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placeholder_elem = ET.SubElement(answers_elem, 'placeholder')
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ET.SubElement(placeholder_elem, 'text').text = '#A'
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answermark_elem = ET.SubElement(answers_elem, 'answermark')
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ET.SubElement(answermark_elem, 'text').text = '1'
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answertype_elem = ET.SubElement(answers_elem, 'answertype')
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ET.SubElement(answertype_elem, 'text').text = '0'
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numbox_elem = ET.SubElement(answers_elem, 'numbox')
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ET.SubElement(numbox_elem, 'text').text = '2'
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# Berechnungsvariablen
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vars1_elem = ET.SubElement(answers_elem, 'vars1')
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vars1_elem_text = f'g = gcd(d[0],d[1]);\ncd = d[0]*d[1]/pow(g,2);\ne = [cd / d[0], cd / d[1]];\nnums = [n[0]*e[0], n[1]*e[1]];\nthesumnum = nums[0] + nums[1]'
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ET.SubElement(vars1_elem, 'text').text = vars1_elem_text
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# Antwort
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answer_elem = ET.SubElement(answers_elem, 'answer')
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answer_text = f'[thesumnum, cd]'
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ET.SubElement(answer_elem, 'text').text = answer_text
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answernotunique_elem = ET.SubElement(answers_elem, 'answernotunique')
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ET.SubElement(answernotunique_elem, 'text').text = '0'
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vars2_elem = ET.SubElement(answers_elem, 'vars2')
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vars2_elem_text = u"<![CDATA[ ga = _0 == thesumnum && _1 == cd; gb = (_0 / _1) == (thesumnum / cd); ]]>"
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ET.SubElement(vars2_elem, 'text').text = vars2_elem_text
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correctness_elem = ET.SubElement(answers_elem, 'correctness')
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ET.SubElement(correctness_elem, 'text').text = 'ga + 0.5*gb'
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unitpenalty_elem = ET.SubElement(answers_elem, 'unitpenalty')
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ET.SubElement(unitpenalty_elem, 'text').text = '1'
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postunit_elem = ET.SubElement(answers_elem, 'postunit')
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ET.SubElement(postunit_elem, 'text').text = ' '
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ruleid_elem = ET.SubElement(answers_elem, 'ruleid')
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ET.SubElement(ruleid_elem, 'text').text = '1'
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otherrule_elem = ET.SubElement(answers_elem, 'otherrule')
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ET.SubElement(otherrule_elem, 'text').text = ' '
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# Unterfragen-Text
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subqtext_elem = ET.SubElement(answers_elem, 'subqtext', attrib={'format': 'html'})
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sub_question_text = '''<![CDATA[ <p>Berechne:</p> <p>\\(\\Large \\displaystyle \\frac{{n[0]}}{{d[0]}} + \\frac{{n[1]}}{{d[1]}} =\\) {_0} / {_1}</p> ]]> '''
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ET.SubElement(subqtext_elem, 'text').text = sub_question_text
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# Lösungshinweis
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feedback_elem = ET.SubElement(answers_elem, 'feedback', attrib={'format': 'html'})
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feedback_text = '''<![CDATA[ <h4>Lösungshinweis</h4>
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<p>Die korrekte Lösung ist:</p>
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<p>\\(\\Large \\displaystyle \\frac{{n[0]}}{{d[0]}} + \\frac{{n[1]}}{{d[1]}} = \\frac{{nums[0]}}{{cd}} + \\frac{{nums[1]}}{{cd}} = \\frac{{thesumnum}}{{cd}}\\) </p> ]]>'''
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ET.SubElement(feedback_elem, 'text').text = feedback_text
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# correctfeedback
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correctfeedback_elem = ET.SubElement(answers_elem, 'correctfeedback', attrib={'format': 'html'})
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correctfeedback_text = '''<![CDATA[ <p>Richtig!</p>]]>'''
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ET.SubElement(correctfeedback_elem, 'text').text = correctfeedback_text
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# partially correct feedback
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pcorrectfeedback_elem = ET.SubElement(answers_elem, 'partiallycorrectfeedback', attrib={'format': 'html'})
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pcorrectfeedback_text = '''<![CDATA[ <p>Teilweise richtig.</p>]]>'''
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ET.SubElement(pcorrectfeedback_elem, 'text').text = pcorrectfeedback_text
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# incorrect feedback
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incorrectfeedback_elem = ET.SubElement(answers_elem, 'incorrectfeedback', attrib={'format': 'html'})
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incorrectfeedback_text = '''<![CDATA[ <p>Leider nicht richtig.</p>]]>'''
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ET.SubElement(incorrectfeedback_elem, 'text').text = incorrectfeedback_text
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return question
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def generate_questions(num_questions):
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"""Generiert Aufgaben für die Addition ungleichnamiger Brüche."""
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questions = []
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for i in range(num_questions):
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numerator1 = random.randint(1, 10)
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denominator1 = random.randint(2, 10)
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numerator2 = random.randint(1, 10)
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denominator2 = random.randint(2, 10)
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# Sicherstellen, dass die Nenner unterschiedlich sind
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while denominator1 == denominator2:
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denominator2 = random.randint(2, 10)
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question = create_formula_question(numerator1, denominator1, numerator2, denominator2, i)
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questions.append(question)
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return questions
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def create_quiz(questions):
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"""Erzeugt die gesamte Quiz-Struktur."""
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quiz = ET.Element('quiz')
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for q in questions:
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quiz.append(q)
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return quiz
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def save_to_file(xml_element, filename):
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"""Speichert das XML-Dokument in einer Datei."""
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tree = ET.ElementTree(xml_element)
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with open(filename, 'wb') as f:
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tree.write(f, encoding='utf-8', xml_declaration=True)
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# Hauptprogramm
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if __name__ == "__main__":
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num_questions = 1 # Anzahl der zu generierenden Aufgaben
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questions = generate_questions(num_questions)
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quiz = create_quiz(questions)
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save_to_file(quiz, 'formulas_fraction_addition_quiz.xml')
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print("Moodle-XML-Datei 'formulas_fraction_addition_quiz.xml' erfolgreich erstellt.")
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10
formulas_fraction_addition_quiz.xml
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10
formulas_fraction_addition_quiz.xml
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<?xml version='1.0' encoding='utf-8'?>
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<quiz><question type="formulas"><name><text>Addition von 2 ungleichnamigen Brüchen 0</text></name><questiontext format="html"><text><![CDATA[ <p>Addiere die Brüche und kürze das Ergebnis so weit wie möglich.</p>
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<p>{#A} </p> ]]> </text></questiontext><generalfeedback format="html"><text> </text></generalfeedback><defaultgrade>1.0000000</defaultgrade><penalty>0.3333333</penalty><hidden>0</hidden><idnumber> </idnumber><correctfeedback format="html"><text><![CDATA[ <p>Die Antwort ist richtig.</p> ]]> </text></correctfeedback><partiallycorrectfeedback format="html"><text><![CDATA[ <p>Die Antwort ist teilweise richtig.</p> ]]> </text></partiallycorrectfeedback><incorrectfeedback format="html"><text><![CDATA[ <p>Die Antwort ist falsch.</p> ]]></text></incorrectfeedback><shownumcorrect /><varsrandom><text> </text></varsrandom><varsglobal><text>n = [5, 3];
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d = [9, 6];</text></varsglobal><answernumbering><text>ABCD</text></answernumbering><answers><partindex><text>0</text></partindex><placeholder><text>#A</text></placeholder><answermark><text>1</text></answermark><answertype><text>0</text></answertype><numbox><text>2</text></numbox><vars1><text>g = gcd(d[0],d[1]);
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cd = d[0]*d[1]/pow(g,2);
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e = [cd / d[0], cd / d[1]];
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nums = [n[0]*e[0], n[1]*e[1]];
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thesumnum = nums[0] + nums[1]</text></vars1><answer><text>[thesumnum, cd]</text></answer><answernotunique><text>0</text></answernotunique><vars2><text><![CDATA[ ga = _0 == thesumnum && _1 == cd; gb = (_0 / _1) == (thesumnum / cd); ]]></text></vars2><correctness><text>ga + 0.5*gb</text></correctness><unitpenalty><text>1</text></unitpenalty><postunit><text> </text></postunit><ruleid><text>1</text></ruleid><otherrule><text> </text></otherrule><subqtext format="html"><text><![CDATA[ <p>Berechne:</p> <p>\(\Large \displaystyle \frac{{n[0]}}{{d[0]}} + \frac{{n[1]}}{{d[1]}} =\) {_0} / {_1}</p> ]]> </text></subqtext><feedback format="html"><text><![CDATA[ <h4>Lösungshinweis</h4>
|
||||
<p>Die korrekte Lösung ist:</p>
|
||||
<p>\(\Large \displaystyle \frac{{n[0]}}{{d[0]}} + \frac{{n[1]}}{{d[1]}} = \frac{{nums[0]}}{{cd}} + \frac{{nums[1]}}{{cd}} = \frac{{thesumnum}}{{cd}}\) </p> ]]></text></feedback><correctfeedback format="html"><text><![CDATA[ <p>Richtig!</p>]]></text></correctfeedback><partiallycorrectfeedback format="html"><text><![CDATA[ <p>Teilweise richtig.</p>]]></text></partiallycorrectfeedback><incorrectfeedback format="html"><text><![CDATA[ <p>Leider nicht richtig.</p>]]></text></incorrectfeedback></answers></question></quiz>
|
||||
@ -0,0 +1,117 @@
|
||||
<?xml version="1.0" encoding="UTF-8"?>
|
||||
<quiz>
|
||||
<!-- question: 35853 -->
|
||||
<question type="formulas">
|
||||
<name>
|
||||
<text>Addition von 2 ungleichnamigen Brüchen</text>
|
||||
</name>
|
||||
<questiontext format="html">
|
||||
<text>
|
||||
<![CDATA[<p>Addiere die Brüche und kürze das Ergebnis so weit wie möglich.</p><p>{#A}</p>]]>
|
||||
</text>
|
||||
</questiontext>
|
||||
<generalfeedback format="html">
|
||||
<text></text>
|
||||
</generalfeedback>
|
||||
<defaultgrade>1.0000000</defaultgrade>
|
||||
<penalty>0.3333333</penalty>
|
||||
<hidden>0</hidden>
|
||||
<idnumber></idnumber>
|
||||
<correctfeedback format="html">
|
||||
<text>
|
||||
<![CDATA[<p>Die Antwort ist richtig.</p>]]>
|
||||
</text>
|
||||
</correctfeedback>
|
||||
<partiallycorrectfeedback format="html">
|
||||
<text>
|
||||
<![CDATA[<p>Die Antwort ist teilweise richtig.</p>]]>
|
||||
</text>
|
||||
</partiallycorrectfeedback>
|
||||
<incorrectfeedback format="html">
|
||||
<text>
|
||||
<![CDATA[<p>Die Antwort ist falsch.</p>]]>
|
||||
</text>
|
||||
</incorrectfeedback>
|
||||
<shownumcorrect/>
|
||||
<varsrandom>
|
||||
<text></text>
|
||||
</varsrandom>
|
||||
<varsglobal>
|
||||
<text>n = [3, 7];
|
||||
d = [2, 3];</text>
|
||||
</varsglobal>
|
||||
<answernumbering>
|
||||
<text>ABCD</text>
|
||||
</answernumbering>
|
||||
<answers>
|
||||
<partindex>
|
||||
<text>0</text>
|
||||
</partindex>
|
||||
<placeholder>
|
||||
<text>#A</text>
|
||||
</placeholder>
|
||||
<answermark>
|
||||
<text>1</text>
|
||||
</answermark>
|
||||
<answertype>
|
||||
<text>0</text>
|
||||
</answertype>
|
||||
<numbox>
|
||||
<text>2</text>
|
||||
</numbox>
|
||||
<vars1>
|
||||
<text>g = gcd(d[0],d[1]);
|
||||
cd = d[0]*d[1]/pow(g,2);
|
||||
e = [cd / d[0], cd / d[1]];
|
||||
nums = [n[0]*e[0], n[1]*e[1]];
|
||||
thesumnum = nums[0] + nums[1]</text>
|
||||
</vars1>
|
||||
<answer>
|
||||
<text>[thesumnum, cd]</text>
|
||||
</answer>
|
||||
<answernotunique>
|
||||
<text>0</text>
|
||||
</answernotunique>
|
||||
<vars2>
|
||||
<text>
|
||||
<![CDATA[ga = _0 == thesumnum && _1 == cd;
|
||||
gb = (_0 / _1) == (thesumnum / cd);]]>
|
||||
</text>
|
||||
</vars2>
|
||||
<correctness>
|
||||
<text>ga + 0.5*gb</text>
|
||||
</correctness>
|
||||
<unitpenalty>
|
||||
<text>1</text>
|
||||
</unitpenalty>
|
||||
<postunit>
|
||||
<text></text>
|
||||
</postunit>
|
||||
<ruleid>
|
||||
<text>1</text>
|
||||
</ruleid>
|
||||
<otherrule>
|
||||
<text></text>
|
||||
</otherrule>
|
||||
<subqtext format="html">
|
||||
<text>
|
||||
<![CDATA[<p>Berechne:</p><p>\(\Large \displaystyle \frac{{n[0]}}{{d[0]}} + \frac{{n[1]}}{{d[1]}} =\) {_0} / {_1}</p>]]>
|
||||
</text>
|
||||
</subqtext>
|
||||
<feedback format="html">
|
||||
<text>
|
||||
<![CDATA[<h4>Lösungshinweis</h4><p>Die korrekte Lösung ist:</p><p>\(\Large \displaystyle \frac{{n[0]}}{{d[0]}} + \frac{{n[1]}}{{d[1]}} = \frac{{nums[0]}}{{cd}} + \frac{{nums[1]}}{{cd}} = \frac{{thesumnum}}{{cd}}\)</p>]]>
|
||||
</text>
|
||||
</feedback>
|
||||
<correctfeedback format="html">
|
||||
<text></text>
|
||||
</correctfeedback>
|
||||
<partiallycorrectfeedback format="html">
|
||||
<text></text>
|
||||
</partiallycorrectfeedback>
|
||||
<incorrectfeedback format="html">
|
||||
<text></text>
|
||||
</incorrectfeedback>
|
||||
</answers>
|
||||
</question>
|
||||
</quiz>
|
||||
Loading…
Reference in New Issue
Block a user